Need to setup client --connect option Windows 2003

rniziak

All,

I have a Windows 2003 R2 client that needs to auto-connect with no user intervention on reboot...
I have the client.ovpn file in the config directory and have the openvpn connect service
starting as a service.. I cannot find the correct registry change in order to have
the service start with the --connect option..

Regards,

RJN.

maikcat

if you set openvpn service to autostart,it simply tries to
start openvpn using config files found in program files\openvpn\config directory.

your win installation uses 32bit or 64bit OS?
can you post the contents of your .ovpn file?

Michael.

rniziak

This is the directory structure I have... C:\Program Files\OpenVPN Technologies\OpenVPN Client

Should I be using a different client ??

THX,

RJN

janjust

that's the non-community version of the client and should be used only if you use OpenVPN Access Server; for all other purposes try the community version: http://swupdate.openvpn.org/community/releases/openvpn-2.2.2-install.exe

rniziak

I installed that version, copied my client.ovpn file into the config directory, configured it as a service, started the vpngui manually and logged in and got connected.. from that poing the system should be able to reboot on re-connect automatically .. correct?? or am I missing something?? It still will not connect on bootup..

In the status box, I get a "NOTE: OpenVPN 2.1 requires '--script-security 2' or higher to call user-defined scripts or executables" message

janjust

the openvpn service will start all configuration files (*.ovpn) found in the directory

 c:\program files\openvpn\config

(for 64bit:

 c:\program files (x86)\openvpn\config

disconnect the VPN , stop the gui, then do a 'net start openvpnservice' - is the VPN active after that? if so, configure this service to be started at system startup time.